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Zarg · Familiar Face Joined: 09 Mar 2008 Posts: 10

Hello everybody!

I use g_timeout_add to run the following code once per second:

Code: (C)
1 2 3 4 5 6 7 8 9 10 11 12	void update (void) { FILE *output; // char temp[100]; output = popen("ls", "r"); // save output to temp char pclose(output); g_print ("Hello World\n"); return; }

This will (of course) print useless "Hello World"s to the command line ...
The problem is that if I uncomment line 4 I'll only get one "Hello World"! It seems that the code only gets executed once ... what's the problem with chars and g_timeout_add?

Thank you for your help!

Last edited by Zarg on Wed Apr 02, 2008 5:47 am; edited 1 time in total

Wolfgang · Familiar Face Joined: 05 Feb 2008 Posts: 37

update() function must be gboolean. It should return TRUE if timeout loop must be repeated. And your function returns random value that depends on register eax (on i8086) value.

Zarg · Familiar Face Joined: 09 Mar 2008 Posts: 10

Thank you!

That really helped! :)

But it's really strange that it always worked without the char declaration and never worked with it ... anyway, problem solved! :)