GTK+ Forums

Dpux · Joined: 22 Jul 2008 Posts: 2

i have just started programming in gtk,and i havent got any gui programmin experience till now, so pardon me if this question sounds too stupid :)
here is a snippet of the code i went through :

button=gtk_button_new_with_label("button1");
g_signal_connect(G_OBJECT(button),"clicked",G_CALLBACK(callback),(gpointer)"button1");
gtk_table_attach_defaults(GTK_TABLE(table),button,0,1,0,1);
gtk_widget_show(button);
button=gtk_button_new_with_label("button2");
g_signal_connect(G_OBJECT(button),"clicked",G_CALLBACK(callback),(gpointer)"button2");
gtk_widget_show(button);

i cant understand, why we have the same name "button" for two different buttons; this should create problem as button is a pointer itself and so changing it should change the widget created, and not the copy of the widget.how is this happening ??

Vadi · GTK+ Geek Joined: 28 May 2008 Posts: 68

button becomes another object when you create a button on it.

Dpux · Joined: 22 Jul 2008 Posts: 2

yes it seems to me so. but i wanted to know the mechanism of creating the new button with the same name...

Vadi · GTK+ Geek Joined: 28 May 2008 Posts: 68

I think you're confusing the button name and a button label.

You cannot have two buttons with the same name, but you can have two buttons with the same label.

dreblen · Posted: Tue Jul 22, 2008 11:34 pm Post subject:

you could (theoretically) use the same GtkWidget* variable for every widget in your program, because the gtk_*_new() functions just return a pointer to a newly created object,
although, you probably shouldn't really do that.

so to answer your question, the reason you can use the same variable is because the gtk_*_new() functions return a pointer,
it doesn't care what was held in the variable before